Regexp help

[NickFitz]

The spaces comeout as 0xa0 if the come from a 'real' space and 0x20 if the come from a  

I put the XML through JTidy to get the DOM.

Never even know there were 2 types of space and the debugger clearly never knew the difference.

Recon i'm jusy going to replace all the 0x20 to 0xa0s

Cheers.

Yup, 0xa0 (aka 160) is the non-breaking space. Therefore,

[\s\xa0]-[\s\xa0]

should do what you want

[minestrone]

That is how you lose 2 hours doing the most trivial of things that should be easy.

Cheers.