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Wind power goes with the cube of wind speed too. So halving the wind speed means 1/8 the power. Though power also goes with the square of the rotor radius, so that can just be increased in length by (windspeed fraction) ^ -1.5
I thought May was windy. And cold. People are walking around in winter clothes and it's almost June ffs. I think the temperature maxed out at 12 degrees C a few days ago. It's almost June for flips sake. Cold, wet windy. Not a bad climate in summer actually, were it not for the winter temperatures dropping to -18 degrees C </end rant>.
On the other hand, to estimate the typical power, we shouldn’t take the
mean wind speed and cube it; rather, we should find the mean cube of the
windspeed. The average of the cube is bigger than the cube of the average.
Didn't some scottish boffin recently report that while scottish independence was economically viable, there wasn't all that much in it - and there was certainly a lot of hot air going around.
In particular, he pointed out that while there were still some oil reserves, the so-called wind reserves of Scotland were a complete falacy. All these wind farms being built are loss making - and are subsided by the state.
Isn't that just saying to find the average wind power, take the average of the power not the power of the average wind? If so, that is pretty obvious albeit a very easy mistake to make.
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