Maths problem

[Doggy Styles]

(although if you know all the distinct percentages but not the number of repetitions of each, then it's a variant of the Frobenius Coin Problem)

Does that apply to the unobtainable score of 19 in a cribbage hand, and whatever it is in rugby union?

[Olly]

oi oi ...EO....comeeeeeeon old chap...tell me that scribbled bit of barely pseudo code is eeeeeeeeeexactly what you're looking for
Tell me what language you're using and I might even see if I can smarten it up appropriately.

[EternalOptimist]

oi oi ...EO....comeeeeeeon old chap...tell me that scribbled bit of barely pseudo code is eeeeeeeeeexactly what you're looking for
Tell me what language you're using and I might even see if I can smarten it up appropriately.

It's VBA


I got round it by looping through the values and jiggling with the number type.
not quite as good as a dither, but it works
users say they will accept diferent numbers for the same % , so long as the bottom line is correct


public dblRoundmeUpAS double
public lngLastRoundmeUp as long

function RoundmeUp(myVal)


dblRoundmeUp = dblRoundmeUp + myVal
RoundmeUp = CLng(dblRoundmeUp) - lngLastRoundmeUp
lngLastRoundmeUp = dblRoundmeUp

end

I'm sh1t as maths me