Originally posted by TheFaQQer
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Reply to: SQL Left Join
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Previously on "SQL Left Join"
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Using SQl Server 2008 here. Will run both variants through Query Analyzer & look at execution plans when I've got some time.
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One more thing....Originally posted by lilelvis2000 View PostWouldn't using a not exists clause work better?
eg: select a* from tableA a
where not exists (select * from TableB b where b.id=a.id)
You'd need to include a check for both columns being null in the two tables, if the database doesn't use an equals operator on nulls (e.g. Oracle)
Code:SELECT a.* FROM tableA a WHERE NOT EXISTS ( SELECT * FROM tableB b WHERE b.id = a.id OR ( b.id IS NULL and a.id IS NULL ) )
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If the column in one of the tables is nullable, and in the other table is not nullable, then Oracle uses the same execution plan regardless of whether you use NOT EXISTS or a join:
Code:SQL > create table cuk1(id number, 2 constraint cuk1_pk primary key(id)); Table created. SQL > create table cuk2(id number); Table created. SQL > begin 2 for i in 1..100 loop 3 insert into cuk1 values(i); 4 end loop; 5 commit; 6 end; 7 / PL/SQL procedure successfully completed. SQL > begin 2 for i in 1..100000 loop 3 insert into cuk2 4 values(mod(i,97)); 5 end loop; 6 commit; 7 end; 8 / PL/SQL procedure successfully completed. SQL > create index cuk2_idx on cuk2(id); Index created. SQL > exec dbms_stats.gather_table_stats(USER,'CUK1'); PL/SQL procedure successfully completed. SQL > exec dbms_stats.gather_table_stats(USER,'CUK2'); PL/SQL procedure successfully completed. SQL > -- Not exists check..... SQL > explain plan for 2 select id from cuk1 a 3 where not exists 4 (select 1 from cuk2 b where b.id=a.id); Explained. SQL > select * from table(dbms_xplan.display); PLAN_TABLE_OUTPUT ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------ Plan hash value: 1819530608 ------------------------------------------------------------------------------ | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ------------------------------------------------------------------------------ | 0 | SELECT STATEMENT | | 4 | 24 | 50 (4)| 00:00:01 | |* 1 | HASH JOIN ANTI | | 4 | 24 | 50 (4)| 00:00:01 | | 2 | INDEX FULL SCAN | CUK1_PK | 100 | 300 | 1 (0)| 00:00:01 | | 3 | TABLE ACCESS FULL| CUK2 | 100K| 292K| 48 (3)| 00:00:01 | ------------------------------------------------------------------------------ Predicate Information (identified by operation id): --------------------------------------------------- 1 - access("B"."ID"="A"."ID") 15 rows selected. SQL > -- Outer join check SQL > explain plan for 2 select a.id 3 from cuk1 a 4 left outer join cuk2 b on (a.id = b.id) 5 where b.id is null; Explained. SQL > select * from table(dbms_xplan.display); PLAN_TABLE_OUTPUT ------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------------ Plan hash value: 1819530608 ------------------------------------------------------------------------------ | Id | Operation | Name | Rows | Bytes | Cost (%CPU)| Time | ------------------------------------------------------------------------------ | 0 | SELECT STATEMENT | | 4 | 24 | 50 (4)| 00:00:01 | |* 1 | HASH JOIN ANTI | | 4 | 24 | 50 (4)| 00:00:01 | | 2 | INDEX FULL SCAN | CUK1_PK | 100 | 300 | 1 (0)| 00:00:01 | | 3 | TABLE ACCESS FULL| CUK2 | 100K| 292K| 48 (3)| 00:00:01 | ------------------------------------------------------------------------------ Predicate Information (identified by operation id): --------------------------------------------------- 1 - access("A"."ID"="B"."ID") 15 rows selected. SQL > drop table cuk1; Table dropped. SQL > drop table cuk2; Table dropped.
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It depends on whether the column is nullable or not, and (probably) which database you are using.Originally posted by wurzel View PostWould one perform better than the other?
In MySQL, for example, left join performs well where both columns are not-nullable. However, it performs badly where one or both of the columns is nullable, in which case an EXISTS / NOT EXISTS would perform better.
You could also use a NOT IN instead of NOT EXISTS, which (I think!) would work best, although if the column is nullable then you would need to include an additional check for nulls.
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You would need to try it. go on.Originally posted by wurzel View PostPerfect thanks.
Would one perform better than the other?
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Perfect thanks.Originally posted by TheFaQQer View PostIt depends on what you want
The difference is that the join condition in the second cursor may return no rows (there are no rows in b with a null ID). This means that (a.id=b.id AND b.id IS NULL) essentially means that you return everything in TableA......
Would one perform better than the other?Originally posted by lilelvis2000 View PostWouldn't using a not exists clause work better?
eg: select a* from tableA a
where not exists (select * from TableB b where b.id=a.id)
though
select a* from TableA a left join TableB b on a.id=b.id
where b.id IS NULL
is another way to go.
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Wouldn't using a not exists clause work better?
eg: select a* from tableA a
where not exists (select * from TableB b where b.id=a.id)
though
select a* from TableA a left join TableB b on a.id=b.id
where b.id IS NULL
is another way to go.
Leave a comment:
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It depends on what you wantOriginally posted by wurzel View PostWhat approach is correct?
The difference is that the join condition in the second cursor may return no rows (there are no rows in b with a null ID). This means that (a.id=b.id AND b.id IS NULL) essentially means that you return everything in TableA.Originally posted by wurzel View PostSELECT a.* FROM TableA a
LEFT JOIN TableB b ON a.id = b.id
WHERE b.id IS NULL
SELECT a.* FROM TableA a
LEFT JOIN TableB b ON (a.id = b.id AND b.id IS NULL)
Code:SQL > CREATE table CUK1 (id number); Table created. Elapsed: 00:00:00.48 SQL > begin 2 for i in 1..4 loop 3 insert into cuk1 values (i); 4 end loop; 5 commit; 6 end; 7 / PL/SQL procedure successfully completed. Elapsed: 00:00:00.46 SQL > SQL > create table cuk2 (id number); Table created. Elapsed: 00:00:00.48 SQL > SQL > begin 2 for i in 3..4 loop 3 insert into cuk2 values (i); 4 end loop; 5 commit; 6 end; 7 / PL/SQL procedure successfully completed. Elapsed: 00:00:00.48 SQL > select * from cuk1; ID ---------- 1 2 3 4 Elapsed: 00:00:00.59 SQL > select * from cuk2; ID ---------- 3 4 Elapsed: 00:00:00.59 SQL > select cuk1.id, cuk2.id 2 from cuk1 LEFT OUTER JOIN cuk2 ON (cuk1.id = cuk2.id); ID ID ---------- ---------- 3 3 4 4 1 2 Elapsed: 00:00:00.64 SQL > SELECT a.* FROM cuk1 a 2 LEFT JOIN cuk2 b ON a.id = b.id 3 WHERE b.id IS NULL; ID ---------- 1 2 Elapsed: 00:00:00.61 SQL > SELECT a.* FROM cuk1 a 2 LEFT JOIN cuk2 b ON (a.id = b.id AND b.id IS NULL); ID ---------- 1 2 3 4 Elapsed: 00:00:00.60 SQL > SELECT a.* 2 FROM cuk1 a 3 JOIN cuk2 b ON ( a.id = b.id ); ID ---------- 3 4 Elapsed: 00:00:00.62 SQL > SELECT a.* FROM cuk1 a 2 LEFT JOIN cuk2 b ON a.id = b.id 3 WHERE b.id IS NOT NULL; ID ---------- 3 4 Elapsed: 00:00:00.59 SQL > drop table cuk1; Table dropped. Elapsed: 00:00:00.51 SQL > SQL > drop table cuk2; Table dropped. Elapsed: 00:00:00.57 SQL >
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SQL Left Join
Apologies if this is is a very basic question but my SQL is a bit rusty these days.
Simple scenario, I have 2 tables, A & B and I want to return everything form table A that doesn't have a corresponding record in B. So I've tried the followwing 2 statements:
SELECT a.* FROM TableA a
LEFT JOIN TableB b ON a.id = b.id
WHERE b.id IS NULL
SELECT a.* FROM TableA a
LEFT JOIN TableB b ON (a.id = b.id AND b.id IS NULL)
They both return different results. I would have expected the results to be same for both.
What approach is correct?Tags: None
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