Reply to: C# test - no googling

[KentPhilip]

You need to have your mouth cleaned...

That won't be possible. You know the listerine dragon clifford, I made him swallow his own fire, and he cooked himself

[AtW]

The only shorts I'm interested in are served in a small glass or worn by a half-naked lady...

You need to have your mouth cleaned...

[Freamon]

What a stupid design.

Principle of least astonishment - Wikipedia, the free encyclopedia

[jamesbrown]

I am sure that works the same in java although I really can't be arsed opening up an editor and testing it.

Yep. A shortcut would be z = x += y, no pun intended.

[KentPhilip]

The only shorts I'm interested in are served in a small glass or worn by a half-naked lady...

[mudskipper]

Maybe the compiler infers the type of "x + y" to be an int since it could overflow a short. Then youd have to cast that explicitly to a short to assign to "z".

That would make sense if int+int = long as well. But it doesn't.

[minestrone]

You are close.

Yes the compiler assigns the number as integers, because there is no + operator on a short! Then of course the implicit conversion of an int to a short fails at compile time.

I am sure that works the same in java although I really can't be arsed opening up an editor and testing it.

[SimonMac]

Have you tried turning it off and on again?

[VectraMan]

Yes the compiler assigns the number as integers, because there is no + operator on a short! Then of course the implicit conversion of an int to a short fails at compile time.

That's just plain stoopid.

It'll work in C. Should have called it Cb obviously.

[DimPrawn]

You are close.

Yes the compiler assigns the number as integers, because there is no + operator on a short! Then of course the implicit conversion of an int to a short fails at compile time.

[amcdonald]

Why does it try and assign them as integers?

Can't remember why, when the shorts were declared I assume it implicitly converts them from integers to shorts, but when you try and add the x and y it tries to pass a reference to x and y as integers ?

[aussielong]

Why does the following not compile?

short x = 2, y = 3;
short z = x + y; // Compile-time error

Maybe the compiler infers the type of "x + y" to be an int since it could overflow a short. Then youd have to cast that explicitly to a short to assign to "z".

[eek]

y ends up an integer not a short.

Then the implicit conversion fails as you can't implicitly convert to a short.

[bless 'em all]

Can I ask Bob?

He's asking ATW.

[DimPrawn]

Does it try and assign x and y both as integers, without casting them to a short thus throwing an exception ?

Why does it try and assign them as integers?