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Reply to: P = Np ?

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Previously on "P = Np ?"

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  • Diestl
    replied

    Leave a comment:


  • NotAllThere
    replied
    On the other hand, even if you axiomise P=NP (or P#NP), you'll still get undecidability in your problem space.

    Leave a comment:


  • threaded
    replied
    Depends totally on the axioms for the problem space.

    If the axiom set can be used to prove P=NP then yes, if they can prove the opposite, then the answer is no.

    Simples.

    threaded in "please save us from GCSEs in IT" mode

    Leave a comment:


  • TimberWolf
    started a topic P = Np ?

    P = Np ?

    Interesting article here about recent status/developments in the most open question in computer science, mathematics, logic, physics...

    Highlights include that factoring and finding discrete logarithms are not thought to be NP-complete (these are used in cryptography), that whether P=NP may never be known and that quantum computers would probably not help solve NP complete problems.

    I also read recently that 15 had been successfully factored by quantum computer. Although a classical computer was required to complete the job.

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