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Previously on "The interior angles of a triangle are"

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  • minestrone
    replied
    Originally posted by BrilloPad View Post


    Its true I only hold a degree. I did start a phd while at the mod but give it up for the filthy lucre of the city (sorry atw).
    Well if you had any degree of quality you would know chucking about +20 & +30 makes no sense.

    You have to quantify what you put down.

    Leave a comment:


  • minestrone
    replied
    Are we expecting a whole number here?

    Leave a comment:


  • BrilloPad
    replied
    Originally posted by minestrone View Post
    I can see you have no mathematical ability beyond the basic level you hold.


    Its true I only hold a degree. I did start a phd while at the mod but give it up for the filthy lucre of the city (sorry atw).

    Leave a comment:


  • BrilloPad
    replied
    Originally posted by KentPhilip View Post
    I can't work it out. Can someone post the solution, with workings?
    The solution is to give the cleaner 1. Or if you are MTT give her 2.

    Leave a comment:


  • minestrone
    replied
    Originally posted by BrilloPad View Post
    The interior angles of a triangle are :-

    5x+3y
    3x+20
    10y+30

    What is x+y?
    I can see you have no mathematical ability beyond the basic level you hold.

    Leave a comment:


  • Diver
    replied
    Stopit OwlHoot, you'll confuse the boy

    Leave a comment:


  • OwlHoot
    replied
    Originally posted by KentPhilip View Post
    I can't work it out. Can someone post the solution, with workings?
    k2p2 posted a link to the solutions, but one can solve it in a slightly different way (although much the same in principle)

    (5x + 3y) + (3x + 20) + (10 y + 30) = 180 gives 8x + 13y = 130, i.e. 8(x + y) = 5(26 - y)

    Because 5 is prime relative to 8, it must divide x + y, which is say 5z, giving 8z = 26 - y, i.e. 13z = 26 + x (adding x + y (= 5z) to both sides)

    But that means 13 must divide x, which is say 13t, so that (13t + y) = 5(2 + t), i.e. y = 10 - 8t, which for positive x and y forces t = 1.

    Leave a comment:


  • mudskipper
    replied
    Originally posted by KentPhilip View Post
    I can't work it out. Can someone post the solution, with workings?
    http://www.mathcomp.leeds.ac.uk/b_file.php?id=469

    Q25
    Last edited by mudskipper; 29 April 2012, 13:16. Reason: wrong link (again)

    Leave a comment:


  • KentPhilip
    replied
    I can't work it out. Can someone post the solution, with workings?

    Leave a comment:


  • SimonMac
    replied
    (duplicate post)

    Leave a comment:


  • SimonMac
    replied
    Originally posted by BrilloPad View Post

    What is x+y?
    The 24th and 25th letters of the traditional English alphabet

    Leave a comment:


  • Doggy Styles
    replied
    That's one thing the Romans DIDN'T do for us - give us a bloody zero.

    Leave a comment:


  • TimberWolf
    replied
    Originally posted by k2p2 View Post
    So, given the full question, my answer is invalid.
    Yes, it appears that 0 isn't a positive integer (based on a two second search).

    Leave a comment:


  • SupremeSpod
    replied
    Originally posted by Diver View Post
    Would the answer be one of the following;

    A 15
    B 14
    C 13
    D 12
    E 11

    If that's "rule of thumb", it's no wonder you keep trying to sever yours!

    Leave a comment:


  • Diver
    replied
    Originally posted by k2p2 View Post
    So, given the full question, my answer is invalid.
    x=0, y=10, x+y = 10 = invalid

    Leave a comment:

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