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Previously on "The rate of the rate of the rise in rising inflation is falling!"
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In a related item...Did anybody catch the BBC 4 documentary The Story of Maths last night? BBC - BBC Four Programmes - The Story of Maths
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Originally posted by TimberWolf View PostUsually when people go to the trouble to say displacement they refer to the vector quantity describing the shortest path between two points, they don't usually go out of their way to describe displacement as a scalar. Distance is usually the word used for that.
Displacement (vector) - Wikipedia, the free encyclopedia
Anyway, that's my limit. [another pun]
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Originally posted by conned tractor View PostIn the above example, v = dd/dt, since d = x-y.
Would it be easier to understand if it was in s-notation.
Displacement (vector) - Wikipedia, the free encyclopedia
Anyway, that's my limit. [another pun]
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Originally posted by TimberWolf View PostIncidentally displacement is a vector quantity. Not that vectors are relevant anyway, as you can take derivatives of quantities other than vectors! Speed, for example. Thanks for ruining my great little pound pun with all this illiterate nonsense though
Would it be easier to understand if it was in s-notation.
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Originally posted by conned tractor View PostPosition is generally referred to as displacement as it is a scalar quantity, but they are the same in this case.
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Originally posted by rd409 View PostDisplacement is correct here. Displacement is the change in position, and the derivative of this displacement is velocity. The second derivative of displacement is acceleration.
d = x - y (linear displacement)
v = d / t
a = v / t
where x, y are scalar coordinates, d = dispalcement, v = velocity, t = time, and a = acceleration.
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Originally posted by zeitghostStone me, I didn't mean to start the calculus wars all over again.
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Originally posted by TimberWolf View Postposition
The original article was referring to a change in the rate of inflation rather than a third derivative.
d = x - y (linear displacement)
v = d / t
a = v / t
where x, y are scalar coordinates, d = dispalcement, v = velocity, t = time, and a = acceleration.
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Originally posted by TimberWolf View Postposition
The original article was referring to a change in the rate of inflation rather than a third derivative.
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Originally posted by conned tractor View PostSorry buddy, but acceleration is the second derivative of displacement.
The second derivative of velocity is the rate of change of acceleration.
Disclaimer: Not that the original header makes any sesne any how.
The original article was referring to a change in the rate of inflation rather than a third derivative.
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Originally posted by amcdonald View PostIs the third derivative African or European ?
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Originally posted by conned tractor View PostSorry buddy, but acceleration is the second derivative of displacement.
The second derivative of velocity is the rate of change of acceleration.
Disclaimer: Not that the original header makes any sesne any how.
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Originally posted by TimberWolf View PostJust put it into everyday terms. Inflation is the speed of a money printing ball thrown into the air, while the second derivative is the acceleration of the money ball. So if a money ball were thrown into the sky fast enough, and even were the acceleration of the money ball negative, the money ball might never come back and would escape the influence of the money printing machine forever and never come back.
The second derivative of velocity is the rate of change of acceleration.
Disclaimer: Not that the original header makes any sesne any how.Last edited by conned tractor; 12 July 2011, 12:38.
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I'm sorry I cannot be with you this week to take part in all of this gloom, but I have been day trading Yell since last week and have managed to make an extra £12k since Friday to cover any inflation.
Don't let me stop you talking about it though. I'm back off to III.
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Originally posted by TimberWolf View PostJust put it into everyday terms. Inflation is the speed of a money printing ball thrown into the air, while the second derivative is the acceleration of the money ball. So if a money ball were thrown into the sky fast enough, and even were the acceleration of the money ball negative, the money ball might never come back and would escape the influence of the money printing machine forever and never come back.
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