B Bluebird Super poster Thanks received 2 Apr 16, 2007 15:07 #2 0? 0? 0 ? Mind you I only go a "c" O level maths...
Z zeitghost More fingers than teeth Thanks received 1,077 Apr 16, 2007 15:08 #3 That's Golden that is...
B BrilloPad I Am Legend Thanks received 7,628 Apr 16, 2007 15:13 #4 threaded said: (a+b)/a = a/b Click to expand... So ab + b**2 = a**2 a**2 -ab - b**2 = 0 Is there a prize for solving this? Saddest CU poster?
threaded said: (a+b)/a = a/b Click to expand... So ab + b**2 = a**2 a**2 -ab - b**2 = 0 Is there a prize for solving this? Saddest CU poster?
OwlHoot More fingers than teeth Thanks received 544 Apr 16, 2007 18:33 #5 andrew_neil_uk said: So ab + b**2 = a**2 a**2 -ab - b**2 = 0 Is there a prize for solving this? Saddest CU poster? Click to expand... There's quite stiff competition around here. P.S. If a/b = c/d then they both equal (a + c)/(b + d)
andrew_neil_uk said: So ab + b**2 = a**2 a**2 -ab - b**2 = 0 Is there a prize for solving this? Saddest CU poster? Click to expand... There's quite stiff competition around here. P.S. If a/b = c/d then they both equal (a + c)/(b + d)
threaded Godlike Thanks received 38 Apr 17, 2007 08:55 #6 zeitghost said: The Greeks had a word for it... Click to expand... ακροσκαιμεσοσλογος
TheOmegaMan More time posting than coding Thanks received 0 Apr 17, 2007 10:09 #7 The Golden ratio is (1+sqrt(5))/2 and satisfies that equation. However so does the Jabber conjugate of (1-sqrt(5))/2. You are threaded and I claim my Nobel Prize. Last edited: Apr 17, 2007 10:09
The Golden ratio is (1+sqrt(5))/2 and satisfies that equation. However so does the Jabber conjugate of (1-sqrt(5))/2. You are threaded and I claim my Nobel Prize.